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Q. The concentration (in mol/L) of the solution having osmotic pressure $0.0821$ atm at $300\, K$ will be

Uttarkhand PMTUttarkhand PMT 2009

Solution:

$ \pi =CRT $
$ C=\frac{\pi }{RT}=\frac{0.0821}{0.0821\times 300} $
$ =0.33\times 10^{-2}mol/L $