Question

The compound in which carbon uses only its $s{p}^3$ hybrid orbitals for bond formation is

• A. ${\left(C{H}_3\right)}_{3}COH$
• B. $HCOOH$
• C. $C{H}_{3}CHO$
• D. ${\left(H_{2}N\right)}_{2}CO$

Answer 1

Answer: (A)

All bonds are $\text{σ}$ - bonds hence, carbon uses only its $\text{s}{\text{p}}^3$ -hybrid orbitals. In all other compounds there is one $\text{C}=\text{O}$ double bond, therefore, this carbon is $\text{s}{\text{p}}^2$ - hybridized