Question

The compound in which carbon uses only its $sp^{3}$ hybrid orbitals for bond formation is

• A. $\left(C H_{3}\right)_{3}COH$
• B. $HCOOH$
• C. $CH_{3}CHO$
• D. $\left(H_{2} N\right)_{2}CO$

Answer 1

Answer: (A)

All bonds are $\text{σ}$ - bonds hence, carbon uses only its $\text{s}\text{p}^{3}$ -hybrid orbitals. In all other compounds there is one $\text{C}=\text{O}$ double bond, therefore, this carbon is $\text{s}\text{p}^{2}$ - hybridized