The combined capacitance of the arrangement shown in figure given below, in μ F is

Question

The combined capacitance of the arrangement shown in figure given below, in μ F is (A)  (30/11) (B)  (8/11) (C) 4 (D) 1

Tardigrade Admin · Accepted Answer

Capacitors of 6 μ F and 3 μ F are in series, so C' = (6 × 3/6 + 3) = (18/9) = 2 μ F Now C' is in paralleI with 2 uf capacitor, so C = C' + 2 = 2 + 2 = 4 μ F

Q. The combined capacitance of the arrangement shown in figure given below, in $μ F$ is

$\frac{30}{11}$

$\frac{8}{11}$

4

1

Capacitors of $6 μ F an d 3 μ F$ are in series, so
$C^{'} = \frac{6 \times 3}{6 + 3}$
$= \frac{18}{9} = 2 μ F$
Now C' is in paralleI with 2 uf capacitor, so
$C = C^{'} + 2 = 2 + 2 = 4 μ F$

Q. The combined capacitance of the arrangement shown in figure given below, in μF is

1130​

118​

4

1

Capacitors of 6μFand3μF are in series, so C′=6+36×3​ =918​=2μF Now C' is in paralleI with 2 uf capacitor, so C=C′+2=2+2=4μF

Q. The combined capacitance of the arrangement shown in figure given below, in $μ F$ is

$\frac{30}{11}$

$\frac{8}{11}$

Capacitors of $6 μ F an d 3 μ F$ are in series, so
$C^{'} = \frac{6 \times 3}{6 + 3}$
$= \frac{18}{9} = 2 μ F$
Now C' is in paralleI with 2 uf capacitor, so
$C = C^{'} + 2 = 2 + 2 = 4 μ F$