The coils of a step down transformer have 501 and 5000 turns. In the primary coil an AC of 4 A at 2200 V is sent. The value of the current and potential difference in secondary coil will be

Question

The coils of a step down transformer have 501 and 5000 turns. In the primary coil an AC of 4 A at 2200 V is sent. The value of the current and potential difference in secondary coil will be (A) 20 A, 220V (B) 0.4 A, 22000V (C) 40 A, 220 V (D) 40 A, 22000 V

Tardigrade Admin · Accepted Answer

(es/ep)=(Ns/Np) Given, Ns=500, Np=5000, ep=2200 V ∴ es=(Ns/Np) × ep =(500/5000) × 2200=220 V Again (es/ep)=(Ip/Is) or Is=4 × (2200/220)=40 A

Q. The coils of a step down transformer have $501$ and $5000$ turns. In the primary coil an $A C$ of $4 A$ at $2200 V$ is sent. The value of the current and potential difference in secondary coil will be

20 A, 220V

0.4 A, 22000V

40 A, 220 V

40 A, 22000 V

$\frac{e _{s}}{e _{p}} = \frac{N _{s}}{N _{p}}$
Given, $N_{s} = 500, N_{p} = 5000, e_{p} = 2200 V$
$∴ e_{s} = \frac{N _{s}}{N _{p}} \times e_{p}$
$= \frac{500}{5000} \times 2200 = 220 V$
Again $\frac{e _{s}}{e _{p}} = \frac{I _{p}}{I _{s}}$
or $I_{s} = 4 \times \frac{2200}{220} = 40 A$

Q. The coils of a step down transformer have 501 and 5000 turns. In the primary coil an AC of 4A at 2200V is sent. The value of the current and potential difference in secondary coil will be