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  4. The coils of a step down transformer have 501 and 5000 turns. In the primary coil an AC of 4 A at 2200 V is sent. The value of the current and potential difference in secondary coil will be

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Q. The coils of a step down transformer have $501$ and $5000$ turns. In the primary coil an $AC$ of $4\, A$ at $2200 \,V$ is sent. The value of the current and potential difference in secondary coil will be

Chhattisgarh PMTChhattisgarh PMT 2004

Solution:

$\frac{e_{s}}{e_{p}}=\frac{N_{s}}{N_{p}}$
Given, $N_{s}=500, N_{p}=5000, e_{p}=2200 \,V$
$ \therefore e_{s}=\frac{N_{s}}{N_{p}} \times e_{p}$
$=\frac{500}{5000} \times 2200=220 V$
Again $\frac{e_{s}}{e_{p}}=\frac{I_{p}}{I_{s}}$
or $I_{s}=4 \times \frac{2200}{220}=40\, A$