The circuit is as given in figure. The current through the branch BE of the circuit is :-

Question

The circuit is as given in figure. The current through the branch BE of the circuit is :- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-mzbadjq7eifiwvdj.jpg" /> (A) 2A (B) 5A (C) 7A (D) 10A

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-mzbadjq7eififqyg.jpg" /> Applying nodal analysis at B we get (x - 70/2)+(x - 0/4)+(x - (70 - x)/2)=0 ⇒ x=40 ⇒ current in BE=5A

Q. The circuit is as given in figure. The current through the branch $BE$ of the circuit is :-

$2 A$

$5 A$

$7 A$

$10 A$

Applying nodal analysis at $B$ we get
$\frac{x - 70}{2} + \frac{x - 0}{4} + \frac{x - ( 70 - x )}{2} = 0$
$\Rightarrow x = 40$
$\Rightarrow$ current in $BE = 5 A$

Q. The circuit is as given in figure. The current through the branch BE of the circuit is :-

2A

5A

7A

10A