Thank you for reporting, we will resolve it shortly
Q.
The circuit is as given in figure. The current through the branch $BE$ of the circuit is :-
NTA AbhyasNTA Abhyas 2020
Solution:
Applying nodal analysis at $B$ we get
$\frac{x - 70}{2}+\frac{x - 0}{4}+\frac{x - \left(70 - x\right)}{2}=0$
$\Rightarrow x=40$
$\Rightarrow $ current in $BE=5A$