The chloride of a metal contains 71 % chlorine by weight and the vapour density of it is 50 . The atomic mass of the metal will be (valency of metal is 2)

Question

The chloride of a metal contains 71 % chlorine by weight and the vapour density of it is 50 . The atomic mass of the metal will be (valency of metal is 2) (A) 29 (B) 58 (C) 35.5 (D) 71

Tardigrade Admin · Accepted Answer

Mol. wt. of metal chloride =2 × V . D =2 × 50=100 Let at. wt. of metal is x so x+71=100 x=100-71=29

Q. The chloride of a metal contains $71%$ chlorine by weight and the vapour density of it is $50.$ The atomic mass of the metal will be (valency of metal is 2)

29

58

35.5

71

Mol. wt. of metal chloride $= 2 \times V . D$

$= 2 \times 50 = 100$

Let at. wt. of metal is $x$

so $x + 71 = 100$

$x = 100 - 71 = 29$

Q. The chloride of a metal contains 71% chlorine by weight and the vapour density of it is 50. The atomic mass of the metal will be (valency of metal is 2)

29

58

35.5

71

Mol. wt. of metal chloride =2×V.D =2×50=100 Let at. wt. of metal is x so x+71=100 x=100−71=29

Q. The chloride of a metal contains $71%$ chlorine by weight and the vapour density of it is $50.$ The atomic mass of the metal will be (valency of metal is 2)

Mol. wt. of metal chloride $= 2 \times V . D$

$= 2 \times 50 = 100$

Let at. wt. of metal is $x$

so $x + 71 = 100$

$x = 100 - 71 = 29$