Question

The charge present on $2.8g$ of $N^{3-}$ in coulombs is

• A. $5.78\times 10^4$
• B. $36.13\times 10^{22}$
• C. $1.93\times 10^4$
• D. $22.58\times 10^3$

Answer 1

Answer: (A)

Number of ions in $2.8g$ of $N^{3-}=\frac{2.8}{14}\times 6.023\times 10^{23}$

$=12.046\times 10^{22}$

One nitride ion contains 3 unit electronic charge i.e.

$3\times 1.6\times 10^{-19}$ coulomb

$\therefore$ Total charge present on $2.8g{N}^{3-}$ ions

$=12.046\times 10^{22}\times 3\times 1.6\times 10^{-19}=5.78\times 10^4$ coulombs