The change in potential energy when a body of mass m is raised to a height nR from earth's surface is :

Question

The change in potential energy when a body of mass m is raised to a height nR from earth's surface is : (A)  operatornamemgR ( n / n -1) (B) mgR (C)  operatornamemgR ( n / n +1) (D) ( mgR / n )

Tardigrade Admin · Accepted Answer

Δ u =((- GMm / R ( n +1)))-((- GMm / R )) =( GMm / R )(( n / n +1)) Δ u =(( n / n +1)) mgR

Q. The change in potential energy when a body of mass $m$ is raised to a height $n R$ from earth's surface is :

$mgR \frac{n}{n - 1}$

$m g R$

$mgR \frac{n}{n + 1}$

$\frac{m g R}{n}$

$Δ u = (\frac{- GM m}{R ( n + 1 )}) - (\frac{- GM m}{R})$
$= \frac{GM m}{R} (\frac{n}{n + 1})$
$Δ u = (\frac{n}{n + 1}) m g R$

Q. The change in potential energy when a body of mass m is raised to a height nR from earth's surface is :

mgRn−1n​

mgR

mgRn+1n​

nmgR​