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  4. The change in potential energy when a body of mass m is raised to a height nR from earth's surface is :

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Q. The change in potential energy when a body of mass $m$ is raised to a height $nR$ from earth's surface is :

Solution:

$\Delta u =\left(\frac{- GMm }{ R ( n +1)}\right)-\left(\frac{- GMm }{ R }\right)$
$=\frac{ GMm }{ R }\left(\frac{ n }{ n +1}\right)$
$\Delta u =\left(\frac{ n }{ n +1}\right) mgR$