The bulk modulus of a liquid is 3 × 1010 Nm -2. The pressure required to reduce the volume of liquid by 2 % is :

Question

The bulk modulus of a liquid is 3 × 1010 Nm -2. The pressure required to reduce the volume of liquid by 2 % is : (A) 3 × 108 Nm -2 (B) 9 × 108 Nm -2 (C) 6 × 108 Nm -2 (D) 12 × 108 Nm -2

Tardigrade Admin · Accepted Answer

B =3 × 1010 -(Δ V / V )=0.02 B =(Δ P /-(Δ V ) V ) ⇒ Δ P =- B ((Δ V / V )) =(3 × 1010)(0.02) =6 × 108 N / m 2

Q. The bulk modulus of a liquid is $3 \times 1 0^{10} N m^{- 2}$ . The pressure required to reduce the volume of liquid by $2%$ is :

$3 \times 1 0^{8} N m^{- 2}$

$9 \times 1 0^{8} N m^{- 2}$

$6 \times 1 0^{8} N m^{- 2}$

$12 \times 1 0^{8} N m^{- 2}$

$B = 3 \times 1 0^{10}$
$- \frac{Δ V}{V} = 0.02$
$B = \frac{Δ P}{- \frac{Δ V}{V}}$
$\Rightarrow Δ P = - B (\frac{Δ V}{V})$
$= (3 \times 1 0^{10}) (0.02)$
$= 6 \times 1 0^{8} N / m^{2}$

Q. The bulk modulus of a liquid is 3×1010Nm−2. The pressure required to reduce the volume of liquid by 2% is :

3×108Nm−2

9×108Nm−2

6×108Nm−2

12×108Nm−2