Question

The bulk modulus of a liquid is $3 \times 10^{10} \,Nm ^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is :

• A. $3 \times 10^{8}\, Nm ^{-2}$
• B. $9 \times 10^{8} \,Nm ^{-2}$
• C. $6 \times 10^{8} \,Nm ^{-2}$
• D. $12 \times 10^{8} \,Nm ^{-2}$

Answer 1

Answer: (C)

$B =3 \times 10^{10}$
$-\frac{\Delta V }{ V }=0.02$
$B =\frac{\Delta P }{-\frac{\Delta V }{ V }}$
$ \Rightarrow \Delta P =- B \left(\frac{\Delta V }{ V }\right)$
$=\left(3 \times 10^{10}\right)(0.02)$
$=6 \times 10^{8} \,N / m ^{2}$