The bond order of O2+ is the same as in:

Question

The bond order of O2+ is the same as in: (A)  N2+  (B)  CN-  (C)  CO  (D)  NO+

Tardigrade Admin · Accepted Answer

O2+(15e-)=K:K*(σ 2s)2(σ *2s)2 (σ 2px)2(π 2py)2(π 2pz)2(π *2pz)0 Hence, bond order =(1/2)(10-5)=2.5 N2+(134e-)=KK*(σ 2s)2(σ *2s)2(σ 2px)2 (π 2py)2(π 2pz)1 Hence, bond order =(1/2)(9-4)=2.5

Q. The bond order of $O_{2}^{+}$ is the same as in:

$N_{2}^{+}$

$C N^{-}$

$CO$

$N O^{+}$

Q. The bond order of O2+​ is the same as in:

N2+​

CN−

CO

NO+

O2+​(15e−)=K:K∗(σ2s)2(σ∗2s)2 (σ2px​)2(π2py​)2(π2pz​)2(π∗2pz​)0 Hence, bond order =21​(10−5)=2.5 N2+​(134e−)=KK∗(σ2s)2(σ∗2s)2(σ2px​)2 (π2py​)2(π2pz​)1 Hence, bond order =21​(9−4)=2.5

Q. The bond order of $O_{2}^{+}$ is the same as in:

$N_{2}^{+}$

$C N^{-}$

$CO$

$N O^{+}$