1. Tardigrade
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  3. Chemistry
  4. The bond order of O2+ is the same as in:

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Q. The bond order of $ O_{2}^{+} $ is the same as in:

MGIMS WardhaMGIMS Wardha 2004

Solution:

$ O_{2}^{+}(15{{e}^{-}})=K:{{K}^{*}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}} $ $ {{(\sigma 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{(\pi 2{{p}_{z}})}^{2}}{{({{\pi }^{*}}2{{p}_{z}})}^{0}} $ Hence, bond order $ =\frac{1}{2}(10-5)=2.5 $ $ N_{2}^{+}(134{{e}^{-}})=K{{K}^{*}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2{{p}_{x}})}^{2}} $ $ {{(\pi 2{{p}_{y}})}^{2}}{{(\pi 2{{p}_{z}})}^{1}} $ Hence, bond order $ =\frac{1}{2}(9-4)=2.5 $