The bond order of N2+ is :

Question

The bond order of N2+ is : (A)  1.5  (B)  3.0  (C)  2.5  (D)  2.0

Tardigrade Admin · Accepted Answer

Molecular orbital configuration of N2+ is: N2+ = (Ï 1s)2(Ï* 1s)2(Ï2s)2 (Ï*2s)2 ( Ï 2Py)2(Ï2Pz)2(Ï2Px)1 Bond order =(Nb - Na/2) = (9 - 4/2) = 2.5

Q. The bond order of $N_{2}^{+}$ is :

$1.5$

$3.0$

$2.5$

$2.0$

Molecular orbital configuration of $N_{2}^{+}$ is :
$N_{2}^{+} = (σ 1 s)^{2} (σ^{} 1 s)^{2} (σ 2 s)^{2} (σ^{} 2 s)^{2} (π 2 P_{y})^{2} (π 2 P_{z})^{2} (σ 2 P_{x})^{1}$
Bond order $= \frac{N _{b} - N _{a}}{2}$
$= \frac{9 - 4}{2} = 2.5$

Q. The bond order of N2+​ is :

1.5

3.0

2.5

2.0