1. Tardigrade
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  3. Chemistry
  4. The bond order of N2+ is :

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Q. The bond order of $ N_2^+ $ is :

UPSEEUPSEE 2006

Solution:

Molecular orbital configuration of $N_2^+$ is :
$N_2^+ = (σ 1s)^2(σ^* 1s)^2(σ2s)^2 (σ^*2s)^2 ( π 2P_y)^2(π2P_z)^2(σ2P_x)^1$
Bond order $=\frac{N_b - N_a}{2} $
$= \frac{9 - 4}{2} = 2.5$