Question

The bond order of $H_2^{-}$ ion is $\frac{1}{2}$. If it has $2$ bonding electrons, how many antibonding electrons it will have?

• A. $4$
• B. $3$
• C. $2$
• D. $1$

Answer 1

Answer: (D)

Bond order $=\frac{1}{2}\left(N_b-N_a\right)$

$\frac{1}{2}=\frac{1}{2}\left(2-N_a\right)$

$\therefore N_a=2-1=1$