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Chemistry
The bond order of H2â ion is (1/2). If it has 2 bonding electrons, how many antibonding electrons it will have?
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Q. The bond order of $H_2^−$ ion is $\frac{1}{2}$. If it has $2$ bonding electrons, how many antibonding electrons it will have?
UPSEE
UPSEE 2014
Chemical Bonding and Molecular Structure
A
$4$
1%
B
$3$
5%
C
$2$
8%
D
$1$
86%
Solution:
Bond order $=\frac{1}{2}\left(N_{b}-N_{a}\right)$
$\frac{1}{2} =\frac{1}{2}\left(2-N_{a}\right)$
$\therefore N_{a} =2-1=1$