Question

The bond order of $C_2$ molecule is

• A. 1
• B. 2
• C. 0
• D. 3

Answer 1

Answer: (B)

The electronic configuration of $C_2$ molecule is as
$C_2=\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\pi 2p_y^2=\pi 2p_z^2$
Bond order $=\frac{N_b-N_a}{2}$
$=\frac{8-4}{2}$
$=2$