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Q. The bond order of $ C_2$ molecule is

J & K CETJ & K CET 2011Chemical Bonding and Molecular Structure

Solution:

The electronic configuration of $C _{2}$ molecule is as
$C _{2}=\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \pi 2 p_{y}^{2}=\pi 2 p_{z}^{2}$
Bond order $ = \frac{N_b - N_a}{2}$
$=\frac{8-4}{2}$
$=2$