Question

The bond energies in $NO,N{O}^{+}$ and $N{O}^{-}$ follow the order

• A. $N{O}^{+}>NO>N{O}^{-}$
• B. $NO>N{O}^{+}>N{O}^{-}$
• C. $N{O}^{-}>NO>N{O}^{+}$
• D. $N{O}^{+}>N{O}^{-}>NO$

Answer 1

Answer: (A)

Bond order $NO=\frac{1}{2}(10-5)=2.5$
Bond order in $N{O}^{+}=\frac{1}{2}(10-4)=3.0$
Bond order in $N{O}^{-}=\frac{1}{2}(10-6)=2.0$
Since bond energies are directly related to bond order. Therefore correct order of increasing bond energies is $N{O}^{+}>NO>NO$