The bond distance in a diatomic molecule is 1× 10- 8cm . Its dipole moment is 1.2 D . The fractional electronic charge on each atom is

Question

The bond distance in a diatomic molecule is 1× 10- 8cm . Its dipole moment is 1.2 D . The fractional electronic charge on each atom is (A) 0.50 (B) 1.2× 10- 10 (C) 0.25 (D) 1.2

Tardigrade Admin · Accepted Answer

Partial Charge = (D i p o l e m o m e n t/B o n d d i s t a n c e)=(1.2 × 10- 18 e s u c m/1 × 10- 8 c m) =1.2× 10- 10esu Fractional charge =(1.2 × 10- 10/4.8 × 10- 10)=0.25 ( 4.8× 10- 10 is a theoretical value of μ .)

Q. The bond distance in a diatomic molecule is $1 \times 1 0^{- 8} c m$ . Its dipole moment is $1.2 D$ . The fractional electronic charge on each atom is

$0.50$

$1.2 \times 1 0^{- 10}$

$0.25$

$1.2$

Q. The bond distance in a diatomic molecule is 1×10−8cm . Its dipole moment is 1.2D . The fractional electronic charge on each atom is

0.50

1.2×10−10

0.25

1.2

Partial Charge =BonddistanceDipolemoment​=1×10−8cm1.2×10−18esucm​ =1.2×10−10esu Fractional charge =4.8×10−101.2×10−10​=0.25 ( 4.8×10−10 is a theoretical value of μ .)

Q. The bond distance in a diatomic molecule is $1 \times 1 0^{- 8} c m$ . Its dipole moment is $1.2 D$ . The fractional electronic charge on each atom is

$0.50$

$1.2 \times 1 0^{- 10}$

$0.25$

$1.2$