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  4. The bond distance in a diatomic molecule is 1× 10- 8cm . Its dipole moment is 1.2 D . The fractional electronic charge on each atom is

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Q. The bond distance in a diatomic molecule is $ \, 1\times 10^{- 8}cm$ . Its dipole moment is $1.2 \, D$ . The fractional electronic charge on each atom is

NTA AbhyasNTA Abhyas 2020

Solution:

Partial Charge $= \, \frac{D i p o l e \, m o m e n t}{B o n d \, d i s t a n c e}=\frac{1.2 \times 10^{- 18} \, e s u \, c m}{1 \times 10^{- 8} \, c m}$
$=1.2\times 10^{- 10}esu$
Fractional charge $=\frac{1.2 \times 10^{- 10}}{4.8 \times 10^{- 10}}=0.25$
( $4.8\times 10^{- 10}$ is a theoretical value of $\mu $ .)