The binding energy per nucleon of O16 is 7.97MeV and that of O17 is 7.75MeV . The energy (in MeV ) required to remove a neutron from O17 is :-

Question

The binding energy per nucleon of O16 is 7.97MeV and that of O17 is 7.75MeV . The energy (in MeV ) required to remove a neutron from O17 is :- (A) 3.52 (B) 3.64 (C) 4.23 (D) 7.86

Tardigrade Admin · Accepted Answer

The equation is O17 arrow 0n1+O16 ∴ Energy required =B.E. of O17-B.E. of O16 =17× 7.75-16× 7.97=4.23MeV

Q. The binding energy per nucleon of $O^{16}$ is $7.97 M e V$ and that of $O^{17}$ is $7.75 M e V$ . The energy (in $M e V$ ) required to remove a neutron from $O^{17}$ is :-

$3.52$

$3.64$

$4.23$

$7.86$

The equation is $O^{17} \to 0 n^{1} + O^{16}$
$∴$ Energy required $= B . E .$ of $O^{17} - B . E .$ of $O^{16}$
$= 17 \times 7.75 - 16 \times 7.97 = 4.23 M e V$

Q. The binding energy per nucleon of O16 is 7.97MeV and that of O17 is 7.75MeV . The energy (in MeV ) required to remove a neutron from O17 is :-

3.52

3.64

4.23

7.86