1. Tardigrade
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  4. The binding energy per nucleon of O16 is 7.97MeV and that of O17 is 7.75MeV . The energy (in MeV ) required to remove a neutron from O17 is :-

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Q. The binding energy per nucleon of $O^{16}$ is $7.97MeV$ and that of $O^{17}$ is $7.75MeV$ . The energy (in $MeV$ ) required to remove a neutron from $O^{17}$ is :-

NTA AbhyasNTA Abhyas 2020

Solution:

The equation is $O^{17} \rightarrow 0n^{1}+O^{16}$
$\therefore $ Energy required $=B.E.$ of $O^{17}-B.E.$ of $O^{16}$
$=17\times 7.75-16\times 7.97=4.23MeV$