The binding energy per nucleon of deuteron (21H) and helium nucleus (42He) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Question

The binding energy per nucleon of deuteron (21H) and helium nucleus (42He) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is (A) 13.9 MeV (B) 26.9 MeV (C) 23.6 MeV (D) 19.2 MeV

Tardigrade Admin · Accepted Answer

Energy released = total binding energy of product − total binding energy of reactants ⇒ 28 − (2 × 2.2) = 28 − 4.4 = 236 MeV.

Q. The binding energy per nucleon of deuteron $(_{1}^{2} H)$ and helium nucleus $(_{2}^{4} He)$ is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

13.9 MeV

26.9 MeV

23.6 MeV

19.2 MeV

Energy released = total binding energy of product − total binding energy of reactants
$\Rightarrow 28 - (2 \times 2.2) = 28 - 4.4 = 236 M e V$ .

Q. The binding energy per nucleon of deuteron (12​H) and helium nucleus (24​He) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is