1. Tardigrade
  2. Question
  3. Physics
  4. The binding energy per nucleon of deuteron (21H) and helium nucleus (42He) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The binding energy per nucleon of deuteron $\left(^{2}_{1}H\right)$ and helium nucleus $\left(^{4}_{2}He\right)$ is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

AIEEEAIEEE 2004Nuclei

Solution:

Energy released = total binding energy of product − total binding energy of reactants
$⇒ 28 − (2 × 2.2) = 28 − 4.4 = 236\, MeV$.