The binding energies of the atoms of elements A and B are Ea and Eb respectively. Three atoms of the element B fuse to give one atom of element A. This fusion process is accompanied by release of energy e. Then Ea,Eb and e are related to each other as

Question

The binding energies of the atoms of elements A and B are Ea and Eb respectively. Three atoms of the element B fuse to give one atom of element A. This fusion process is accompanied by release of energy e. Then Ea,Eb and e are related to each other as (A)  Ea+e=3Eb  (B)  Ea=3Eb  (C)  Ea-e=3Eb  (D)  Ea+3Eb+e=0

Tardigrade Admin · Accepted Answer

Q= Sigma Br- Sigma Bp Here, Sigma Br=3 Sigma Bb, Sigma Bp=Ea,Q=e ∴ e=3Eb-Ea ∴ Ea+e=3Eb

Q. The binding energies of the atoms of elements $A$ and $B$ are $E_{a}$ and $E_{b}$ respectively. Three atoms of the element $B$ fuse to give one atom of element $A$ . This fusion process is accompanied by release of energy $e$ . Then $E_{a}, E_{b}$ and $e$ are related to each other as

$E_{a} + e = 3 E_{b}$

$E_{a} = 3 E_{b}$

$E_{a} - e = 3 E_{b}$

$E_{a} + 3 E_{b} + e = 0$

$Q = Σ B_{r} - Σ B_{p}$
Here, $Σ B_{r} = 3Σ B_{b}, Σ B_{p} = E_{a}, Q = e$
$∴$ $e = 3 E_{b} - E_{a}$
$∴$ $E_{a} + e = 3 E_{b}$

Q. The binding energies of the atoms of elements A and B are Ea​ and Eb​ respectively. Three atoms of the element B fuse to give one atom of element A. This fusion process is accompanied by release of energy e. Then Ea​,Eb​ and e are related to each other as

Ea​+e=3Eb​

Ea​=3Eb​

Ea​−e=3Eb​

Ea​+3Eb​+e=0

Q=ΣBr​−ΣBp​ Here, ΣBr​=3ΣBb​,ΣBp​=Ea​,Q=e ∴ e=3Eb​−Ea​ ∴ Ea​+e=3Eb​