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Q. The binding energies of the atoms of elements $A$ and $B$ are $ {{E}_{a}} $ and $ {{E}_{b}} $ respectively. Three atoms of the element $B$ fuse to give one atom of element $A$. This fusion process is accompanied by release of energy $e$. Then $ {{E}_{a}},{{E}_{b}} $ and $e$ are related to each other as

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Solution:

$ Q=\Sigma {{B}_{r}}-\Sigma {{B}_{p}} $
Here, $ \Sigma {{B}_{r}}=3\Sigma {{B}_{b}},\Sigma {{B}_{p}}={{E}_{a}},Q=e $
$ \therefore $ $ e=3{{E}_{b}}-{{E}_{a}} $
$ \therefore $ $ {{E}_{a}}+e=3{{E}_{b}} $