The basicity of aniline is less than that of cyclohexylamine. This is due to

Question

The basicity of aniline is less than that of cyclohexylamine. This is due to (A) + R effect of - NH2 group (B) -I effect of - NH2 group (C) -R effect of -NH2 group (D) hyperconjugation effect.

Tardigrade Admin · Accepted Answer

-NH2 has a +R effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the N atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.

Q. The basicity of aniline is less than that of cyclohexylamine. This is due to

$+ R$ effect of $- N H_{2}$ group

$- I$ effect of $- N H_{2}$ group

$- R$ effect of $- N H_{2}$ group

hyperconjugation effect.

$- N H_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.

Q. The basicity of aniline is less than that of cyclohexylamine. This is due to

+R effect of −NH2​ group

−I effect of −NH2​ group

−R effect of −NH2​ group

hyperconjugation effect.

−NH2​ has a +R effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the N atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.

$+ R$ effect of $- N H_{2}$ group

$- I$ effect of $- N H_{2}$ group

$- R$ effect of $- N H_{2}$ group

$- N H_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.