Question

The average thermal energy for a mono-atomic gas is : ($k_B$ is Boltzmann constant and T, absolute temperature)

• A. $\frac{1}{2}{k}_{B}T$
• B. $\frac{3}{2}{k}_{B}T$
• C. $\frac{5}{2}{k}_{B}T$
• D. $\frac{7}{2}{k}_{B}T$

Answer 1

Answer: (B)

Average thermal energy $=\frac{3}{2}{K}_{B}T$
(where 3 is translational degree of freedom)
For monoatomic gas total degree of freedom
$f=3$ (translational degree of freedom)