Question

The average thermal energy for a mono-atomic gas is : ($k_B$ is Boltzmann constant and T, absolute temperature)

• A. $\frac {1}{2} k_BT$
• B. $\frac {3}{2} k_BT$
• C. $\frac {5}{2} k_BT$
• D. $\frac {7}{2} k_BT$

Answer 1

Answer: (B)

Average thermal energy $=\frac{3}{2}K_{B}T$
(where 3 is translational degree of freedom)
For monoatomic gas total degree of freedom
$f= 3$ (translational degree of freedom)