Question

The average power dissipated in a pure inductor of inductance $L$ is :

• A. $\frac{L{I}^2}{2}$
• B. $L{I}^2$
• C. $\frac{L{I}^2}{4}$
• D. zero

Answer 1

Answer: (D)

The rate of dissipation of energy in an electrical circuit is called power.
It is given by $P=i_{rms}\times E_{rms}\times \cos \varphi$ In a purely.
inductive circuit resistance is zero,
then phase between current and voltage is $90^{\circ }$ hence,
average power is $P_{\text{avg }}=E_{rms}\times i_{rms}\times \cos 90^{\circ }=0$
Hence, no energy dissipation in the circuit.