Question

The average power dissipated in a pure inductor of inductance $L$ is :

• A. $ \frac{LI^{2}}{2}$
• B. $ LI^{2}$
• C. $ \frac{LI^{2}}{4} $
• D. zero

Answer 1

Answer: (D)

The rate of dissipation of energy in an electrical circuit is called power.
It is given by $P=i_{rms} \times E_{rms} \times \cos \phi$ In a purely.
inductive circuit resistance is zero,
then phase between current and voltage is $90^{\circ}$ hence,
average power is $P_{\text {avg }}=E_{rms} \times i_{rms} \times \cos 90^{\circ}=0$
Hence, no energy dissipation in the circuit.