Question

The average force necessary to stop a hammer with 25 Ns momentum in 0.5 s expressed in N is

• A. 500
• B. 125
• C. 50
• D. 25

Answer 1

Answer: (C)

Impulse = Change in momentum = Force $\times$ time i.e. Force = $\frac{Impulse}{time}=\frac{25}{0.5}$ = 50 N