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  4. The average force necessary to stop a hammer with 25 Ns momentum in 0.5 s expressed in N is

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Q. The average force necessary to stop a hammer with 25 Ns momentum in 0.5 s expressed in N is

Laws of Motion

Solution:

Impulse = Change in momentum = Force $\times$ time i.e. Force = $\frac{Impulse}{time} = \frac{25}{0.5} $ = 50 N