The average depth of Indian ocean is about 3000 m. Find the fractional compression (Δ V/V) of water of the bottom of the ocean. Given, bulk modulus of water is 2.2 × 109 Nm -2 and density of water =1000 kgm -3.

Question

The average depth of Indian ocean is about 3000 m. Find the fractional compression (Δ V/V) of water of the bottom of the ocean. Given, bulk modulus of water is 2.2 × 109 Nm -2 and density of water =1000 kgm -3. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The increase in pressure is Δ p=ρ g h Or Δ p=103 × 9.8 × 3000=29.4 × 106 Nm -2 The volume strain =(Δ V/V)=(Δ p/B) =(29.4 × 106/2.2 × 109)=1.36

Q. The average depth of Indian ocean is about $3000 m$ . Find the fractional compression $\frac{Δ V}{V}$ of water of the bottom of the ocean. Given, bulk modulus of water is $2.2 \times 1 0^{9} N m^{- 2}$ and density of water $= 1000 k g m^{- 3}$ .

The increase in pressure is $Δ p = ρ g h$
Or $Δ p = 1 0^{3} \times 9.8 \times 3000 = 29.4 \times 1 0^{6} N m^{- 2}$
The volume strain $= \frac{Δ V}{V} = \frac{Δ p}{B}$
$= \frac{29.4 \times 1 0 ^{6}}{2.2 \times 1 0 ^{9}} = 1.36$

Q. The average depth of Indian ocean is about 3000m. Find the fractional compression VΔV​ of water of the bottom of the ocean. Given, bulk modulus of water is 2.2×109Nm−2 and density of water =1000kgm−3.

The increase in pressure is Δp=ρgh Or Δp=103×9.8×3000=29.4×106Nm−2 The volume strain =VΔV​=BΔp​ =2.2×10929.4×106​=1.36

Q. The average depth of Indian ocean is about $3000 m$ . Find the fractional compression $\frac{Δ V}{V}$ of water of the bottom of the ocean. Given, bulk modulus of water is $2.2 \times 1 0^{9} N m^{- 2}$ and density of water $= 1000 k g m^{- 3}$ .

The increase in pressure is $Δ p = ρ g h$
Or $Δ p = 1 0^{3} \times 9.8 \times 3000 = 29.4 \times 1 0^{6} N m^{- 2}$
The volume strain $= \frac{Δ V}{V} = \frac{Δ p}{B}$
$= \frac{29.4 \times 1 0 ^{6}}{2.2 \times 1 0 ^{9}} = 1.36$