The atomic numbers of vanadium (V) , chromium (Cr) , manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26 . Which one of these may be expected to have the highest second ionisation enthalpy?

Question

The atomic numbers of vanadium (V) , chromium (Cr) , manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26 . Which one of these may be expected to have the highest second ionisation enthalpy? (A)  V  (B)  Cr  (C)  Mn  (D)  Fe

Tardigrade Admin · Accepted Answer

This is stable EC , hence formation of Cr2+ by second IP requires maximum enthalpy.

Q. The atomic numbers of vanadium $(V)$ , chromium $(C r)$ , manganese $(M n)$ and iron $(F e)$ are respectively $23, 24, 25$ and $26$ . Which one of these may be expected to have the highest second ionisation enthalpy?

$V$

$C r$

$M n$

$F e$

This is stable $EC$ , hence formation of $C r^{2 +}$ by second $I P$ requires maximum enthalpy.

Q. The atomic numbers of vanadium (V) , chromium (Cr) , manganese (Mn) and iron (Fe) are respectively 23,24,25 and 26 . Which one of these may be expected to have the highest second ionisation enthalpy?

V

Cr

Mn

Fe