Equation of the tangent to the hyperbola x2−y2=16 in parametric
form is 4xsecϕ−4ytanϕ=16 ⇒xsecϕ−ytanϕ=4
Solving with y=x and y=−x, we get, A(4(secϕ+tanϕ),4(secϕ+tanϕ)) B(4(secϕ−tanϕ),4(tanϕ−secϕ)) ∴ Area bounded by ΔAOB=∣21(16(tan2ϕ−sec2ϕ)−16(sec2ϕ−tan2ϕ)) =∣∣21(−16−16)∣∣=16sq. units