Q. The area of the region bounded by $y = 16 - x^{2}$ and $x$ -axis is

2453 248 KCETKCET 2021Application of Integrals Report Error

A

$8$ square units

28%

B

$20 π$ square units

11%

C

$16 π$ square units

48%

D

$256 π$ square units

13%

Solution:

$x^{2} + y^{2} = 16$
$\frac{1}{2} π (4)^{2} = 8 π$