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  4. The area of the region bounded by y=√16-x2 and x-axis is

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Q. The area of the region bounded by $y=\sqrt{16-x^{2}}$ and $x$-axis is

KCETKCET 2021Application of Integrals

Solution:

$x^{2}+y^{2}=16$
$\frac{1}{2} \pi(4)^{2}=8 \pi$