Question

The area of the ellipse $\frac{x^2}{4^2}+\frac{y^2}{9^2}=1$ is

• A. $6\pi$ sq. units
• B. $\frac{\pi \left(a^2+b^2\right)}{4}$ sq. units
• C. $\pi \left(a+b\right)$ sq. units
• D. none of these

Answer 1

Answer: (D)

Area of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ between the limits $x=a$ and $x=b$ is $\pi ab$
$\therefore$ Area of the given ellipse $=\pi \times 4\times 9=36\pi$ sq. units.