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Q.
The area of the ellipse $\frac{x^{2}}{4^{2}}+\frac{y^{2}}{9^{2}}=1$ is
Application of Integrals
Solution:
Area of the ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ between the limits $x = a$ and $x = b$ is $\pi ab$
$\therefore \quad$ Area of the given ellipse $=\pi\times4\times9=36\pi$ sq. units.