Question

The area enclosed by $y=3x-5,y=0,x=3$ and $x=5$ is

• A. 12 sq. units
• B. 13 sq. units
• C. $13\frac{1}{2}$ sq. units
• D. 14 sq. units

Answer 1

Answer: (D)

Area $=\underset{3}{\overset{5}{\int }}(3x-5)dx$
$=\frac{3}{2}{\left(x^2\right)}_3^5-5(x{)}_3^5=\frac{3}{2}[25-9]-5(5-3)$
$=\frac{3}{2}16-5(2)=24-10=14$