The area enclosed by the curves y2+4 x=4 and y-2 x=2 is :

Question

The area enclosed by the curves y2+4 x=4 and y-2 x=2 is : (A)  (23/3) (B) (22/3)  (C) 9 (D)  (25/3)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/3a00c980253eb9725889f6e64f6ac701-.png" /> y2+4 x=4 y2=-4(x-1) A=∫ limits-42((4-y2/4)-(y-2/2)) d y=9

Q. The area enclosed by the curves $y^{2} + 4 x = 4$ and $y - 2 x = 2$ is :

$\frac{23}{3}$

$\frac{22}{3}$

$9$

$\frac{25}{3}$

$y^{2} + 4 x = 4$
$y^{2} = - 4 (x - 1)$
$A = - 4 \int 2 (\frac{4 - y ^{2}}{4} - \frac{y - 2}{2}) d y = 9$

Q. The area enclosed by the curves y2+4x=4 and y−2x=2 is :

323​

322​

9

325​

y2+4x=4 y2=−4(x−1) A=−4∫2​(44−y2​−2y−2​)dy=9

Q. The area enclosed by the curves $y^{2} + 4 x = 4$ and $y - 2 x = 2$ is :

$\frac{23}{3}$

$\frac{22}{3}$

$9$

$\frac{25}{3}$

$y^{2} + 4 x = 4$
$y^{2} = - 4 (x - 1)$
$A = - 4 \int 2 (\frac{4 - y ^{2}}{4} - \frac{y - 2}{2}) d y = 9$