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Q. The area enclosed by the curves $y^2+4 x=4$ and $y-2 x=2$ is :

JEE MainJEE Main 2023Application of Integrals

Solution:

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$ y^2+4 x=4 $
$y^2=-4(x-1) $
$ A=\int\limits_{-4}^2\left(\frac{4-y^2}{4}-\frac{y-2}{2}\right) d y=9$