Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The approximate value of √[3]28 is
Q. The approximate value of
3
28
is
1217
260
MHT CET
MHT CET 2009
Report Error
A
3.0037
B
3.037
C
3.0086
D
3.37
Solution:
Let
y
=
3
28
Taking log on both sides, we get
lo
g
y
=
3
1
lo
g
28
=
3
1
×
1.4472
=
0.4824
⇒
y
=
antilog
(
0.4824
)
=
3.037
(approximately)