The approximate time duration in hours to electroplate 30 g of calcium from molten calcium chloride using a current of 5 amp is [At. mass of Ca = 40]

Question

The approximate time duration in hours to electroplate 30 g of calcium from molten calcium chloride using a current of 5 amp is [At. mass of Ca = 40] (A) 8 (B) 80 (C) 10 (D) 16

Tardigrade Admin · Accepted Answer

Ca 2++2 e - longrightarrow Ca ( atcathode ) 1 mol CaCl 2=2 F From Q= it n ⋅ 2 F = it t=(n .2 F/i) =(30/40) × (2 × 96500/5) =28950 s =(28950/60 × 60) h =8.04 h

Q. The approximate time duration in hours to electroplate $30 g$ of calcium from molten calcium chloride using a current of $5 am p$ is [At. mass of $C a = 40$ ]

8

80

10

16

$C a^{2 +} + 2 e^{-} ⟶ C a ($ atcathode $)$

$1 m o l C a C l_{2} = 2 F$

From $Q =$ it

$n \cdot 2 F = i t$

$t = \frac{n .2 F}{i}$

$= \frac{30}{40} \times \frac{2 \times 96500}{5}$

$= 28950 s$

$= \frac{28950}{60 \times 60} h$

$= 8.04 h$

Q. The approximate time duration in hours to electroplate 30g of calcium from molten calcium chloride using a current of 5amp is [At. mass of Ca=40]

8

80

10

16

Ca2++2e−⟶Ca( atcathode ) 1molCaCl2​=2F From Q= it n⋅2F=it t=in.2F​ =4030​×52×96500​ =28950s =60×6028950​h =8.04h

Q. The approximate time duration in hours to electroplate $30 g$ of calcium from molten calcium chloride using a current of $5 am p$ is [At. mass of $C a = 40$ ]

$C a^{2 +} + 2 e^{-} ⟶ C a ($ atcathode $)$

$1 m o l C a C l_{2} = 2 F$

From $Q =$ it

$n \cdot 2 F = i t$

$t = \frac{n .2 F}{i}$

$= \frac{30}{40} \times \frac{2 \times 96500}{5}$

$= 28950 s$

$= \frac{28950}{60 \times 60} h$

$= 8.04 h$